ccvs_void
Sorry for my bad language.
Main class that ad’s other classes from includes
main.php :
define(EXT, '.php');
$config = array(
'path' => array (
'data' => 'data/',
'inc' => 'inc/',
'lang' => 'lng/',
'dl' => 'dl/',
),
...
);
class general {
private $cfg;
public $call = array();
function __construct($configs) {
global ${"$configs"};
$this->cfg = $configs;
}
function _include($filename) {
foreach($this->cfg[path] as $dir) {
if(file_exists($dir.$filename.EXT)) {
include($dir.$filename.EXT);
if(class_exists($filename)) {
$this->call[$filename] = new $filename();
}
return true;
}
}
...
}
$main = new general();
// call profiler->start()
$main->call[profiler]->start();
profiler.php :
class profiler {
// simple profiler
private $time_start;
private function get_time() {
list($usec, $sec) = explode(' ', microtime());
return ((float)$usec + (float)$sec);
}
function start() {
$this->time_start = $this->get_time();
}
function finish() {
return ($this->get_time() - $this->time_start);
}
}
index.php :
require('main.php');
...
$main->call[profiler]->finish();
You can edit $config to add path to other directories, and do $main->_include(‘CLASS) and it will include a script and if class named ‘CLASS exist it will create a new class in call[].
You can easily access class $main->call[‘CLASS]
Thank you for reading.
Klasse/Object Functies
Introductie
Deze functies stellen je in staat informatie op te vragen over klassen en geïnstantieerde objecten. Je kunt bijvoorbeeld de naam van een klasse waartoe een object behoort opvragen of alle eigenschappen en namen van methoden. Met deze functies kun je niet alleen de namen van de klasse opvragen maar ook hoe zijn familie (door overerving) er uit ziet (bijv. opvragen wat de ouder van een bepaald object is).
Voorbeelden
In dit voorbeeld definiëren we een basis klasse en een uitbreiding daarop. De basis klasse Groente beschrijft een groente; of deze eetbaar is en wat zijn kleur is. De subklasse Spinazie voegt een methode toe om deze groente te koken en om er achter te komen of deze reeds gekookt is.
Example#1 klassen.inc
<?php
/* Basis klasse met eigenschappen en methoden */
class Groente {
var $eetbaar;
var $kleur;
function Groente( $eetbaar, $kleur="groen" ) {
$this->eetbaar = $eetbaar;
$this->kleur = $kleur;
}
function is_eetbaar() {
return $this->eetbaar;
}
function welke_kleur() {
return $this->kleur;
}
} /* Einde van klasse Groente */
/* De klasse Spinazie breidt de basis klasse uit. */
class Spinazie extends Groente {
var $gekookt = false;
function Spinazie() {
$this->Groente( true, "groen" );
}
function koken() {
$this->gekookt = true;
}
function is_gekookt() {
return $this->gekookt;
}
} /* Einde van klasse Spinazie */
?>
Vervolgens instantiëren we 2 objecten van deze klassen en geven wat informatie over hun weer, waaronder hun ouderschap. We definiëren ook wat handige functies, maar deze dienen enkel om de informatie mooi weer te geven.
Example#2 test_script.php
<pre>
<?php
include "klassen.inc";
/* Handige functies */
function print_vars($obj) {
$eigenschappen = get_object_vars($obj);
while (list($eigenschap, $waarde) = each($eigenschappen))
echo "\t$eigenschap = $waarde\n";
}
function print_methoden($obj) {
$methoden = get_class_methods(get_class($obj));
foreach ($methoden as $methode_naam)
echo "\tfunction $methode_naam()\n";
}
function klasse_ouderschap($obj, $klasse) {
global $$obj;
if (is_subklasse_of($$obj, $klasse)) {
echo "Object $obj behoort toe klasse ".get_class($$obj);
echo " een subklasse van $klasse\n";
} else {
echo "Object $obj behoort niet tot een subklasse van $klasse\n";
}
}
// Maak 2 objecten
$groente = new Groente(true,"blauw");
$blaadje = new Spinazie();
// Geef informatie over de objecten weer.
echo "\$groente: KLASSE " . get_class($groente) . "\n";
echo "\$blaadje: KLASSE " . get_class($blaadje) . "\n";
echo ", OUDER " . get_parent_class($blaadje) . "\n";
// Geef eigenschappen van $groente weer
echo "\n\$groente: Eigenschappen\n";
print_vars($groete);
// Geef de namen van de methoden van $groente weer
echo "\nblaadje: Methoden\n";
print_methoden($blaadje);
echo "\nOuderschap:\n";
klasse_ouderschap('blaadje', 'Spinazie');
klasse_ouderschap('blaady', 'Groente');
?>
</pre>
Het is belangrijk om te onthouden dat in bovenstaand voorbeeld, het object $blaadje een instantie is van de klasse Spinazie welke een subklasse van Groente is. Daarom zal het script de volgende output geven:
[...]
Ouderschap:
Object $blaadje behoort niet tot een subklasse van Spinazie
Object $blaadje behoort tot klasse Spinazie een subkklasse van Groente
Table of Contents
- call_user_method_array — Roept een door de programmeur gedefinieerde methode aan met een array van parameters [vervangen].
- call_user_method — Roept een methode aan op een door de programmeur gespecificeerd object [vervangen]
- class_exists — Controleert of de gegeven naam bestaat als klasse
- get_class_methods — Retourneert een array met de namen van methodes van een klasse
- get_class_vars — Retourneert een array met alle eigenschappen van een klasse.
- get_class — Retourneert de naam van de klasse waarvan het gegeven object geïnstantieerd is.
- get_declared_classes — Retourneert een array met de namen van alle gedefinieerde klassen.
- get_declared_interfaces — Returns an array of all declared interfaces
- get_object_vars — Retourneert een array met alle eigenschappen van een object
- get_parent_class — Retourneert de klasse naam van de ouder van het gegeven object of klasse naam.
- interface_exists — Checks if the interface has been defined
- is_a — Retourneert TRUE als het gegeven object tot deze klasse behoort of als de klasse een van de ouders is.
- is_subclass_of — Retourneert TRUE als het object deze klasse als een van z'n ouders heeft.
- method_exists — Controleert of de gegeven methode in een klasse definitie voorkomt
- property_exists — Checks if the object or class has a property
add a note
User Contributed NotesKlassen/Objecten functies
zerotwo at bk dot ru
20-Feb-2008 06:50
20-Feb-2008 06:50
ahigerd at timeips dot com
20-Dec-2007 03:02
20-Dec-2007 03:02
To access an object member with an illegal character in the name, use this syntax:
$obj->{'illegal-property:name()'}
This is particularly relevant with the dynamically-generated classes used by, for instance, database objects and the SoapClient class.
pascal dot poncet at netconsult dot com
13-Oct-2005 02:21
13-Oct-2005 02:21
Subject: using "sql_calc_found_rows" in a MySQL query while exploiting result in a PHP db class object.
Hello,
There is a nice function in MySQL that allows to know how many records would have been returned if no "where" clause were set : SQL_CALC_FOUND_ROWS.
If you have create a db object to collect the returned lines, you will be a little perplex when trying to call the result of this function.
Why ?
Simply because the returned field's name is "found_rows()" and obviously it's not possible to call something like :
<?php $result->found_rows() ?>
...as it will try to acces a method, not a property !
Then, the only way to get the right result seems to be the use of a class function, like :
<?php
$db->query("select found_rows()");
$count=current(get_object_vars(current($db->result)));
?>
Of course, if somebody found an other way to solve it, like a special syntax (see the one used with curled arrays in a string), I'm really open to discuss.
Good luck,
Pascal
ia [AT] zoznam [DOT] sk
03-Aug-2005 05:55
03-Aug-2005 05:55
as for zabmilenko's solution:
wouldn't it be better to create it this way?
<?php
// The base class for all db classes
class DB {
protected $connectId;
}
// Class for MySQL, which extends base class
class MySQL extends DB {
function connect () {
$this->connectId = mysql_connect (...);
}
}
// Class for PostgreSQL, which extends base class
class pgSQL extends DB {
function connect () {
$this->connectId = pg_connect (...);
}
}
// and then call constructor like this:
$dbName = "MySQL";
$db = new $dbName ( ... );
// ... which creates an object of class MySQL
?>
zabmilenko at hotmail dot com
27-Jun-2005 07:08
27-Jun-2005 07:08
((PHP5))
I wanted to dynamically choose an extender for a class. This took awhile of playing with it but I came up with a solution. Note that I can't verify how safe it is, but it appears to work for me. Perhaps someone else can shed light on the details:
<?php
class A { var $value = "Class A\n"; }
class B { var $value = "Class B\n"; }
// Uncomment which extender you want. You can use variables as well.
// define('__EXTENDER__', 'A');
define('__EXTENDER__', 'B');
// Use eval to create a wrapper class.
eval('class EXTENDER extends '. __EXTENDER__ . ' { }');
class C extends EXTENDER
{
function __construct()
{
echo $this->value;
}
}
$t = new C;
?>
Outputs: Class B
Practical application: I have a database abstraction system that has individual classes for mysql, pgsql, et al. I want to be able to create a global db class that extends one of the individual db classes depending on the application configuration.
I know that there are probably much better ways of doing this but I haven't reached that level when it comes to classes.
cjones
03-Mar-2005 09:27
03-Mar-2005 09:27
If anyone is interested in looking for a way to dynamically load existing objects into a class, here is what I found very useful.
//---------------------------------------------------------
// Dynamically load External Objects into a class
function objRef ( &$obj ) {
eval("\$this->obj_".get_class($obj)." = \$obj;");
}
//---------------------------------------------------------
// Reference by using: $this->obj_[object Name]->[var|f{}]
Example:
class date { function date ( ) { $this->date = "March 3rd"; } }
class time { function time ( ) { $this->time = "12:30pm"; } }
class show {
function objRef ( &$obj ){
eval("\$this->obj_".get_class($obj)." = \$obj;");
}
function test ( $var ){
echo "$var".$this->obj_date->date." @ ".$this->obj_time->time;
}
}
$date = new date;
$time = new time;
$show = new show;
$show->objRef($date);
$show->objRef($time);
$show->test("Time Now => ");
// Output: Time Now => March 3rd @ 12:30pm
I found the prefix 'obj_' before the class name useful because it helped me to automatically identify external object references when scanning through my scripts. You can omit this if you want. Hope this helps someone.
http://sc.tri-bit.com/ StoneCypher
02-Mar-2005 06:25
02-Mar-2005 06:25
to covertka at muohio dot edu and pillepop2003 at yahoo dot de:
There's a much easier solution to getting a class' name for working with a factory function. Let's assume you're doing something like this:
<?php
function FactoryFunction($whatever, $instancedata) {
switch ($whatever) {
case 'stuff' : return new Stuff($instancedata);
case 'otherstuff' : return new Otherstuff($instancedata);
}
}
?>
Now, consider the named parameter idiom and remember that PHP uses hashes for everything; as a result make the following changes:
<?php
function FactoryFunction($whatever, $instancedata) {
switch ($whatever) {
case 'stuff' : return array('typeis'=>'stuff', 'instance'=>new Stuff($instancedata));
case 'otherstuff' : return array('typeis'=>'otherstuff', 'instance'=>new Otherstuff($instancedata));
}
}
?>
Nice 'n simple. It seems that what the original poster wanted was something like C++ static data members; unfortunately as PHP4 has no static variables at all, there would need to be significant language change to support static-like behavior. If you move to PHP5, the static keyword solves your problem cleanly.
covertka at muohio dot edu
03-Jan-2005 01:27
03-Jan-2005 01:27
To pillepop2003 at yahoo dot de:
I have the same issue. I have a base class that manages database tasks for a number of child classes. One of the functions in the base class is a find() method that returns instances of the child classes. Since find() is usually called as a static method, it needs to know the name of the child class. As you've found, this appears to be impossible to get in an easy fashion.
The only way I've found to get the child class name is to use the debug_traceback() function. This requires me to have a find() method in every child class, but it does work.
Here's an example:
<?php
require_once("Application.php");
class parentClass {
function find() {
$className = NULL;
foreach (debug_backtrace() as $bt) {
if ($bt['function'] == __FUNCTION__) {
$className = $bt['class'];
}
}
// here should be some code to find the proper id, let's assume it was id 1
$id = 1;
return new $className($id);
}
}
class foo extends parentClass {
function __construct($id) {
$this->id = id;
}
function find() {
return parent::find();
}
}
class bar extends parentClass {
function __construct($id) {
$this->id = id;
}
function find() {
return parent::find();
}
}
$a = foo::find();
printf("Type for \$a: %s<br/>\n", get_class($a));
$b = bar::find();
printf("Type for \$b: %s<br/>\n", get_class($b));
?>
iparanoid at gmx dot de
04-Aug-2004 06:17
04-Aug-2004 06:17
To pillepop2003 at yahoo dot de:
It seems to me if there really is no nice way to get the class name in an un-instanciated class, there is a workaround in PHP5 though using static/class variables.
Example:
<?php
class myFoo
{
static $__ClassName = __CLASS__;
static function getClassName()
{
return myFoo::$__ClassName;
}
};
class myFooExtended extends myFoo
{
function __construct()
{
myFooExtended::$__ClassName = __CLASS__;
};
};
?>
However, you'll need to have at least instanciated an object of the class myFooExtended before calling getClassName or introduce some other initialization (the class variable will need to be set at some point to __CLASS__ in the sub-class).
greg at doutromundo dot com
06-Jul-2004 02:58
06-Jul-2004 02:58
As programmers, you're probably more organized than me, but, I do try and maintain some order in my classes and codes and separate them in "packages" as in java.
This helped me keep them organized but caused havok when trying to use them, so what I did was to create a class that handles the loading of classes (which I instanciate in all pages) along with my error handling class all bundled up. This way, I can load my classes with a command similar to
$baseClass->loadClass("package","className"[,"constructor"]);
the function responsible for this has some checking to see if they are loaded and stuff like that...
function loadClass($packageName,$className,$constructor=""){
// if you dont have a constructor declare any function inside
// the class
if ($constructor==""){
$constructor=$className;
}
if(!is_callable(array($className,$constructor))){
if (defined("CLASS_DIR")){
$pkg = CLASS_DIR.$packageName."/";
if (is_dir($pkg)){
// we have a directory with the package name
$cls = $pkg.$className.".class.php";
if(is_file($cls)){
// we have a file
include_once($cls);
}else{
die("Class <b>$className</b> could not be found in package <b>$packageName</b> , please check your instalation");
}
}else{
die("Package <b>$packageName</b> could not be found, please check your instalation");
}
}
}
}
Just remember to define CLASS_DIR as the physical path for the directories where you packages are...
Hope this comes in handy...
Here's an example of a diretory strucutre...
/var/www/classes/ <- this would be CLASS_DIR
in there I have:
package1/
name.class.php
name2.class.php
....
The loadClass would look like: loadClass("package1","name");
Cute and easy
ettinger at consultant dot com
18-Jun-2004 11:59
18-Jun-2004 11:59
Re: Looking for an uninstantiated class
# Loads data from a table into a class object
class LFPDataFactory extends LFPObject {
var $object;
var $class;
var $table;
function LFPDataFactory($args) {
$this->unpackArgs($args); // assigns locals from $args
if (in_array(strtolower($this->class), get_declared_classes())) {
$this->object = new $this->class;
// assemble the columns in the table...
// select their values and put them in our new object...
} else { trigger_error("Class ".$this->class." not found", E_USER_ERROR); }
}
}
$r = new LFPDataFactory("class=LFPLayout,table=layout");
$new_obj = $r->object; // this is a LFPLayout object.
print_r($new_obj);
This class looks to see if the class exists, then instantiates it -- a declared class is not the same as an instantiated class. As long as LFPLayout exists somewhere in the scripts, get_declared_classes() will find it. Remember strtolower on compare, however.
Why would I do this? Because I have my class layouts the same as their respective tables; the factory then selects the data (making sure that the variables match) and plugs in the data. (I've left out the actual code to do the selection/insertion).
HOC
28-May-2004 04:40
28-May-2004 04:40
to pillepop2003
Why do u want to know the classname of an non-existant object?
The only possible explanation for this question seems to me u want to know the class before u instantiate the object. Well, this is of no use since u always instantiate a class of ur choice.
When the class is instantiated into an object u can find the class of the object by means of get_class(). This is all u need. In case of inheritance u can use get_class($this) to get the class of the instantiated object. Now u can differentiate according to which class the object belongs to.
e.g.:
<?php
class A{
function A(){
$class_of_this = get_class($this);
echo 'Object is an instance of class '.$class_of_this.' which is the ';
if(strcmp($class_of_this,'A')==0)
echo 'parent-class';
else if(strcmp($class_of_this,'B')==0)
echo 'child-class';
echo ".\n";
}
}
class B extends A{
function B(){
$this->A();
}
}
$object1 = new A();
$object2 = new B();
?>
When u run this code-snippet the output will be:
Object is an instance of class A which is the parent-class.
Object is an instance of class B which is the child-class.
ar at 5mm de
28-Aug-2003 02:59
28-Aug-2003 02:59
I missed some kind of function to dynamicly override or extend an Object:
-----------------------------------------
function &extendObj(&$obj, $code) {
static $num = 0;
$classname = get_class($obj);
$newclass = $classname.$num;
eval('class '.$newclass.' extends '.$classname.' { '.$code.' }');
$newobj = new $newclass();
$vars = get_class_vars($classname);
foreach($vars AS $key=>$value) {
$newobj->$key = &$obj->$key;
}
return $newobj;
}
-----------------------------------------
This creates a new class which extends the old one by the given code parameter, instanciates it and copy all vars from the old obj to the new one.
-----------------------------------------
class testA {
var $prop = 'a';
function funcA($val) {
$this->prop = $val;
}
function value() {
return $this->prop;
}
}
$obj = new testA();
$newobj = &extendObj(&$obj, 'function addX() { $this->prop .= "x"; }');
$newobj->funcA('abc');
$newobj->addX();
echo $newobj->value();
-----------------------------------------
Results in 'abcx'. You can use the function multiple times and also with class variables. Be carefull, even if $newobj is just a copy of $obj, $obj->value() will return 'abcx', too, because of the & operator: $newobj->$key = &$obj->$key;
zidsu at hotmail dot com
08-Jul-2003 12:24
08-Jul-2003 12:24
FYI: if you want to split your class into manageble chunks, what means different files for you, you can put you functoins into includes, and make include() have a return value. Like this:
class Some_class {
var $value = 3;
function add_value ($input_param) {
return include ("path/some_file.php");
}
}
And your included file:
$input_param += $this->value;
return $input_param;
Then your function call will be:
$instance = new Some_class ();
$instance->add_value (3);
And this will return
6
hopefully :P
Keep in mind though, that the scope in the included file will be identical to the scope the function 'add_value' has.
And if you want to return the outcome, you should also have a return statement made in your include as well.
asommer*at*as-media.com
20-Sep-2002 09:52
20-Sep-2002 09:52
Something I found out just now that comes in very handy for my current project:
it is possible to have a class override itself in any method ( including the constructor ) like this:
class a {
..function ha ( ) {
....if ( $some_expr ) {
......$this = new b;
......return $this->ha ( );
....}
....return $something;
..}
}
in this case assuming that class b is already defined and also has the method ha ( )
note that the code after the statement to override itself is still executed but now applies to the new class
i did not find any information about this behaviour anywhere, so i have no clue wether this is supposed to be like this and if it might change... but it opens a few possibilities in flexible scripting!!
einhverfr at not-this-host dot hotmail dot com
14-Sep-2002 07:35
14-Sep-2002 07:35
You may find it helpful in complex projects to have namespaces for your classes, and arrange these in a hierarchical manner. A simple way to do this is to use the filesystem to order your hierarchies and then define a function like this:
function use_namespace($namespace){
require_once("namespaces/$namespace.obj.php");
}
(lack of indentation due to HTML UI for this page)
This requires that all your object libraries end in .obj.php (which I use) but you can modfy it to suit your needs. To call it you could, for exmaple call:
use_namespace("example");
or if foo is part of example you can call:
use_namespace("example/foo");
justin at quadmyre dot com
19-Aug-2002 04:38
19-Aug-2002 04:38
If you want to be able to call an instance of a class from within another class, all you need to do is store a reference to the external class as a property of the local class (can use the constructor to pass this to the class), then call the external method like this:
$this->classref->memberfunction($vars);
or if the double '->' is too freaky for you, how about:
$ref=&$this->classref;
$ref->memberfunction($vars);
This is handy if you write something like a general SQL class that you want member functions in other classes to be able to use, but want to keep namespaces separate. Hope that helps someone.
Justin
Example:
<?php
class class1 {
function test($var) {
$result = $var + 2;
return $result;
}
}
class class2{
var $ref_to_class=''; # to be pointer to other class
function class1(&$ref){ #constructor
$this->ref_to_class=$ref; #save ref to other class as property of this class
}
function test2($var){
$val = $this->ref_to_class->test($var); #call other class using ref
return $val;
}
}
$obj1=new class1;
# obj1 is instantiated.
$obj2=new class2($obj1);
# pass ref to obj1 when instantiating obj2
$var=5;
$result=obj2->test2($var);
# call method in obj2, which calls method in obj1
echo ($result);
?>
gateschris at yahoo dot com
08-Mar-2001 09:59
08-Mar-2001 09:59
[Editor's note: If you are trying to do overriding, then you can just interrogate (perhaps in the method itself) about what class (get_class()) the object belongs to, or if it is a subclass of a particular root class.
You can alway refer to the parent overriden method, see the "Classes and Objects" page of the manual and comments/editor's notes therein.]
There is no function to determine if a member belongs to a base class or current class eg:
<?php
class foo {
function foo () { }
function a () { }
}
class bar extends foo {
function bar () { }
function a () { }
}
lala = new Bar();
?>
------------------
how do we find programmatically if member a now belongs to class Bar or Foo.